(x-2)(x^2+2x-5)=

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Solution for (x-2)(x^2+2x-5)= equation: 


Simplifying
(x + -2)(x2 + 2x + -5) = 0

Reorder the terms:
(-2 + x)(x2 + 2x + -5) = 0

Reorder the terms:
(-2 + x)(-5 + 2x + x2) = 0

Multiply (-2 + x) * (-5 + 2x + x2)
(-2(-5 + 2x + x2) + x(-5 + 2x + x2)) = 0
((-5 * -2 + 2x * -2 + x2 * -2) + x(-5 + 2x + x2)) = 0
((10 + -4x + -2x2) + x(-5 + 2x + x2)) = 0
(10 + -4x + -2x2 + (-5 * x + 2x * x + x2 * x)) = 0
(10 + -4x + -2x2 + (-5x + 2x2 + x3)) = 0

Reorder the terms:
(10 + -4x + -5x + -2x2 + 2x2 + x3) = 0

Combine like terms: -4x + -5x = -9x
(10 + -9x + -2x2 + 2x2 + x3) = 0

Combine like terms: -2x2 + 2x2 = 0
(10 + -9x + 0 + x3) = 0
(10 + -9x + x3) = 0

Solving
10 + -9x + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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